asked 168k views
4 votes
In a lucky draw, ten names are out in a box out of which three are to be taken out. Find the number of total ways in which we can take four names out.

asked
User Zarrah
by
8.1k points

1 Answer

4 votes

Step 1

Given;


\begin{gathered} Ten\text{ names in a box} \\ 3\text{ names are to be taken out} \end{gathered}

Required; To find the number of ways in which we can take out four names

Step 2

Find the number of total ways in which we can take four names out.​

Here, we will take out three names. Thus selection is four without having botheration about ordering the selection.

Thus, the possible number of ways for finding three names out of ten from the box will be :


nC_r=(n!)/(r!(n-r)!)

where;


\begin{gathered} n=10 \\ r=4 \end{gathered}
nCr=(10!)/(4!(10-4)!)
nCr=(3628800)/(24(720))=210\text{ ways}

Answer;


210\text{ ways}

answered
User Alex Vayda
by
8.5k points

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