asked 223k views
0 votes
A certain disease has an incidence rate of 0.6%. If the false negative rate is 4% and the false positive rate is 4%, computethe probability that a person who tests positive actually has the disease.Give your answer accurate to at least 3 decimal places. (13 decimal places)

asked
User Tvl
by
7.5k points

1 Answer

2 votes

Given:

A certain disease has an incidence rate 0.6%. If the false negative rate is 4% and the false positive rate is 4%.

To know:

Probability that a person who tests positive actually has the disease.

Step-by-step explanation:

We can use Bayes theorem to calculate.

Solution:


\begin{gathered} P\left(disease\left|positive\right?\right)=(\left(0.006\right)\left(0.96\right))/(\left(0.006\right)\left(0.96\right)+\left(0.994\right)\left(0.04\right)) \\ \approx0.126 \end{gathered}

Hence 0.126 is the required probability.

answered
User Resnbl
by
7.9k points
Welcome to Qamnty — a place to ask, share, and grow together. Join our community and get real answers from real people.