About 2% of the population has a particular genetic mutation. 900 people are randomly selected.Find the mean for the number of people with the genetic mutation in such groups of…

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asked Feb 10, 2023 219k views

1 Answer

Errnesto · Answer 1 · 2023-02-14T16:06:45+0000

We need to find the mean for the number of people with the genetic mutation in a group of 900.

We know that the probability of each person having that genetic mutation is 2%. Thus, this is a binomial distribution, with:

$p=2\%=(2)/(100)$

Therefore, for a number n of people, the mean μ is given by:

$\mu=n\cdot p$

Thus, for n = 900, we have:

$\mu=900\cdot(2)/(100)=(900)/(100)\cdot2=9\cdot2=18$

Answer: 18