asked 168k views
3 votes
Suppose 25 fou bettes are loondisturbed in a warehouse in the belle population double steevery week the equation Ps23. can be used to determine the umber of beeies er weeksComote the tableWeekPopulation134Question 12Calculate the averagegro

Suppose 25 fou bettes are loondisturbed in a warehouse in the belle population double-example-1
Suppose 25 fou bettes are loondisturbed in a warehouse in the belle population double-example-1
Suppose 25 fou bettes are loondisturbed in a warehouse in the belle population double-example-2
asked
User Trizz
by
7.6k points

1 Answer

2 votes

Answer

Question 1

Option C is correct.

Runner A and B are tied.

Question 2

Option B is correct.

Runner B is the faster runner in this time period.

Question 3

Option A is correct.

Runner A is the faster runner in this time period.

Step-by-step explanation

Average speed is distance covered divided by time taken.

Question 1

For the first 9 seconds

Runner A

Distance covered = 120 - 0 = 120 m

Time Taken = 9 - 0 = 9 seconds

Average speed = (120/9) = 13.33 m/s

Runner B

Distance covered = 120 - 0 = 120 m

Time Taken = 9 - 0 = 9 seconds

Average speed = (120/9) = 13.33 m/s

Both runners are tied.

Question 2

For 9 seconds to 20 seconds

Runner A

Distance covered = 168 - 120 = 48 m

Time Taken = 20 - 9 = 11 seconds

Average speed = (48/11) = 4.36 m/s

Runner B

Distance covered = 213 - 120 = 93 m

Time Taken = 20 - 9 = 11 seconds

Average speed = (93/11) = 8.45 m/s

Runner B is the faster runner in this time period.

Question 3

For 20 to 31 seconds

Runner A

Distance covered = 287 - 168 = 119 m

Time Taken = 31 - 20 = 11 seconds

Average speed = (119/11) = 10.82 m/s

Runner B

Distance covered = 287 - 213 = 74 m

Time Taken = 31 - 20 = 11 seconds

Average speed = (74/11) = 6.73 m/s

Runner A is the faster runner in this time period.

Question 4

For 0 to 31 seconds

Runner A

Distance covered = 287 - 0 = 287 m

Time Taken = 31 - 0 = 31 seconds

Average speed = (287/31) = 9.26 m/s

Runner B

Distance covered = 287 - 0 = 287 m

Time Taken = 31 - 0 = 31 seconds

Average speed = (287/31) = 9.26 m/s

Both runners are tied in this time interval.

Hope this Helps!!!

answered
User Mark Lister
by
8.3k points
Welcome to Qamnty — a place to ask, share, and grow together. Join our community and get real answers from real people.