Question

Given: -7+3x^2-5x20) write the polynomial in standard form.a) -7+3x^2-5x b) 3x^2-5x-7. c) -7-5x+3x^221) identify the coefficient of the first term when the polynomial is written in standard form.a)-7. b) -5. c) -3. d) 322) identify the constant.a) -7 b) -5. c) -3. d) 323) identify the coefficient of the second term when the polynomial is written standard form.a) -7. b) -5. c) -3. d) 3

Answer 1

i) 3x² - 5x - 7 (option B)

ii) 3 (option D)

iii) -7 (option A)

iv) -5 (option B)

Step-by-step explanation:
`\begin{gathered} \text{Given:} \\ -7+3x^2-5x \end{gathered}`

i) To write a polynomial in standard form, the terms will be arranged according to the degrees. The term with the highest degree will come first, followed by the term with the next highest and so on. That is the degrees will be arranged in descending order

From the given polynomial, the highest degree is 2 followed by 1 and then a constant

Re-arranging:

`3x^2\text{ - 5x - 7 (option B)}`

ii) The first term when arranged in standard form is 3x²

So, the first term when the polynomial is written in standard form is 3 (option D)

iii) The constant is a number without a variable (without x)

The constant is -7 (option A)

iv) The second term when re-arranged in standard form is -5x

The coefficient of the second term when the polynomial is written standard form is -5 (option B)