Question

QuestionSolve: -2a3 + 2a2 + 12a = 0.(Use a comma to separate multiple solutions.)a=?

Answer 1

Answer:

The solutions are:

(-2, 0, 3)

Step-by-step explanation:

Given the equations:

`-2a^3+2a^2+12a=0`

This can be written as:

`-2a(a^2-a-6)=0`

So that

`\begin{gathered} -2a=0 \\ \Rightarrow a=0 \\ OR \\ a^2-a-6=0 \\ (a-3)(a+2)=0 \\ a-3=0 \\ \Rightarrow a=3 \\ \\ OR \\ a+2=0 \\ \Rightarrow a=-2 \end{gathered}`

The solutions are:

(-2, 0, 3)