How do I find the X and y value in this type of triangle?

Question

asked Jan 19, 2023 107k views

1 Answer

Isquierdo · Answer 1 · 2023-01-24T16:11:01+0000

The given triangle is a right-angled triangle

Recall that

$\tan \theta=\frac{Opposite\text{ side}}{\text{Adjacent side}}$

$Let\text{ }\theta=x,\text{ then Opposite side=6 and adjacent side =4.}$

$\text{Substitute known values in }\tan \theta=\frac{Opposite\text{ side}}{\text{Adjacent side}}\text{ as follows:}$

$\tan x=(6)/(4)$

$\tan x=(3)/(2)$

$x=\tan ^(-1)((3)/(2))$

$Substitute\tan ^(-1)((3)/(2))=56.30\text{ as follows:}$

$x\approx56^o$

Using the triangle sum property, we get

$Substitutex=56^o\text{ as follows:}$

Hence the values of x and y are

$x=56^o\text{ and }y=34^o$