A car slows to a stop with an average acceleration of – 2.5 m/s2. How long will it take to slow the car from 12 m/s to a position of rest?

Question

asked Oct 9, 2023 209k views

1 Answer

Justin Warner · Answer 1 · 2023-10-13T23:03:41+0000

Given:

The acceleration of the car is

$a=-2.5\text{ m/s}^2$

The initial velocity is

$v_i=\text{ 12 m/s}$

The final velocity is

$v_f=\text{ 0 m/s}$

Required: The time taken by the car to reach the position of rest.

Explanation:

The time can be calculated by the formula

On substituting the values, the time will be

$\begin{gathered} t=(0-12)/(-2.5) \\ =4.8\text{ s} \end{gathered}$

Final Answer: The time taken by the car is 4.8 s.