Question

Triangle QRS has coordinates Q(-6, 6), R(-6, 0) and S(0,0). Translate triangle QRS 7 units right , then rotated 90 clockwise about the origin. What are the coordinates of the final image?

Answer 1

The rule for translating a point 7 units to the right is given by

`(x,y)\to(x+7,y)`
`\begin{gathered} Q^{^(\prime)}=(-6+7,6) \\ Q^{^(\prime)}=(1,6) \\ R^{^(\prime)}=(-6+7,0) \\ R^{^(\prime)}=(1,0) \\ S^{^(\prime)}=(0+7,0) \\ S^{^(\prime)}=(7,0) \end{gathered}`
`\begin{gathered} \text{For 90}^0\text{ clockwise about the origin, the translation becomes:} \\ (x,y)\rightarrow(y,-x) \end{gathered}`

Hence, the coordinates of the final image are:

`\begin{gathered} Q^{^(\doubleprime)}=(6,-1) \\ R^{^(\doubleprime)}=(0,-1) \\ S^{^(\doubleprime)}=(0,-7) \end{gathered}`