Question

What is the area of a rectangle with vertices at (-3, -1),(1, 3),(3, 1) and (-1, -3)?

Answer 1

The rectangle is given by:

The area of this rectangle is given by:

`\begin{gathered} A=w\cdot h \\ \end{gathered}`

Where:

`\begin{gathered} w=\sqrt[]{(3-(-1))^2+(1-(-3))^2} \\ w=4\sqrt[]{2} \end{gathered}`
`\begin{gathered} h=\sqrt[]{(-1-(-3))^2+(-3-(-1))^2} \\ h=2\sqrt[]{2} \end{gathered}`

Therefore:

`\begin{gathered} A=4\sqrt[]{2}\cdot2\sqrt[]{2} \\ A=16 \end{gathered}`

Answer:

16 units²