Question

Is this ansewrs correct?

Answer 1

Using the quadratic formula to solve the equation, we get:

`\begin{gathered} x_(1,2)=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a} \\ x_(1,2)=\frac{1\pm\sqrt[]{(-1)^2-4\cdot3\cdot(-3)}}{2\cdot3} \\ x_(1,2)=\frac{1\pm\sqrt[]{37}}{6} \\ x_1\approx(1+6.08)/(6)\approx1.18 \\ x_2\approx(1-6.08)/(6)\approx-0.847 \end{gathered}`

Answer: {1.2, -0.8}