Question

What do you estimate the value of acceleration due to gravity to be close to the Earth? Why do you think it will be this value?

Answer 1

Step-by-step explanation:

the value of acceleration due to gravity on the surface of the earth is

`g=9.8\text{ m/s}^2`

as we know, the gravity is related as,

`g=(GM)/(R^2)`

Here,

`G=6.67*10^(-11)\text{ N m}^2\text{ /kg}^2`

is a Gravitational constant,

`m=5.972*10^(24)\text{ kg}`

is the mass of the earth and

`R=6.371*10^3\text{ Km}`

is the radius of the earth,

After plugging all the values in the above relation we get

`\begin{gathered} g=\frac{6.67*10^(-11)Nm^2/kg^2*5.972*10^(24)kg}{6.371*10^6\text{ m}}\text{ } \\ g\approx9.8\text{ m/s}^2 \end{gathered}`

Thus, we get acceleration due to gravity is

`9.8\text{ m/s}^2`