Question

The vertices of the polygon are A (3, 5), B (6, 5), C (6, 9), and D (3, 9). Find the distance between the vertices B and C.

Answer 1

The distance (d) formula is

`d=√((x_2-x_1)^2+(y_2-y_1)^2)`

Given:

`\begin{gathered} B=(x_(1,)y_1)=(6,5) \\ C=(x_2,y_2)=(6,9) \end{gathered}`

Therefore,

`d=BC=√((6-6)^2+(9-5)^2)=√(0^2+4^2)=√(16)=4`

Hence, the distance between the vertices B and C is 4.