Question

The circle is centered at the origin and has a arduous of 8. What is it's equation

Answer 1

The general equation of a circle is:

`(x-h)^2+(y-k)^2=r^2`

where (h, k) is the center and r is the radius of the circle.

In this case, the center is the point (0,0), the origin, and the radius is 8. Substituting this information into the equation, we get:

`\begin{gathered} (x-0)^2+(y-0)^2=8^2 \\ x^2+y^2=64 \end{gathered}`