Question

Write the equation of a line that passes through the points (2, -10) and (-4,-7)in slope-intercept form.

Answer 1

the equation is of the form y = mx + b,

`m=(y2-y1)/(x2-x1)=(-7-(-10))/(-4-2)=(-7+10)/(-6)=(3)/(-6)=-(1)/(2)`

for b:

`\begin{gathered} -10=-(1)/(2)(2)+b \\ -10=-1+b \\ -10+1=-1+b+1 \\ b=-9 \end{gathered}`

the equation is

`y=-(1)/(2)x-9`