Question

(The question is in the photo Sorry lol) A sample of a gas occupies 1212 milliliters at 20.0°C and 6756 torr. What volume would it occupy at the same temperature and 289 torr?Answer in units of mL.Please leave all the numbers after the decimal in the final answer

Answer 1

To solve this problem we need to use Boyles gas Law:

`P_1V_1=P_2V_2`

Given:

V1 = 1212 mL

P1 = 6756 Torr

P2 = 289 Torr

V2= ?

V2 = P1V1/P2

V2 = (6756 torr x 1212 mL)/289 torr

V2 = 28333.12111 mL