Question

A rectangular painting measures 13 inches by16 inches and contains a frame of uniformwidth around the four edges. The perimeter ofthe rectangle formed by the painting and itsframe is 82 inches. Determine the width of theframeWhat is the width of the frame?inch(es)

Answer 1

Since the perimeter of the painting and the frame is 82 inches we can write an expression to calculate it, considering that there is a part x over and below the painting.

Therefore the perimeter can be written:

(13+2x)+(13+2x)+(16+2x)+(16+2x)=82

26+4x+32+4x=82

58+8x=82

8x=82-58

8x=24

x=3

Given the fact that x is 3

Then the width of the frame is 16+ 2(3) = 22 inches