Question

Solve the following problem. Be sure to show all steps (V.E.S.T.) and work in order to receive full credit

Answer 1

`\begin{gathered} \text{Let:} \\ x=\text{First number} \\ y=\text{Sencond number} \\ z=\text{Third number} \\ x+y+z=26 \end{gathered}`

The second number is twice than the first, so:

`y=2x`

The third number is 6 more than the second, so:

`z=2x+6`

Replacing the data into the equation:

`\begin{gathered} x+2x+2x+6=26 \\ 5x+6=26 \\ \text{Solving for x:} \\ 5x=26-6 \\ 5x=20 \\ x=(20)/(5) \\ x=4 \end{gathered}`

And:

`\begin{gathered} y=2(4)=8 \\ z=2(4)+6=8+6=14 \\ 4+8+14=26 \\ \text{Which is correct} \end{gathered}`