Question

The flux through the coils of asolenoid changes from2.57*10^-5 Wb to 9.44*10^-5 Wbin 0.0154 s. If 4.08 V of EMF isgenerated, how many loops doesthe solenoid have?(No unit)

Answer 1

We know that EMF in a coil is given as:

`\xi=-N(\Delta\Phi_B)/(\Delta t)`

Plugging the values given we have:

`\begin{gathered} 4.08=-N((2.57*10^(-5)-9.44*^(-5)))/(0.0154) \\ 4.08=(6.87*10^(-5))/(0.0154)N \\ 4.08=4.461*10^(-3)N \\ N=914.59 \end{gathered}`