Question

Which is a polar form of the following parametric equations?x=5cos² thetay = 5 cos theta sin theta

Answer 1

ANSWER

`r(\theta)=5cos\theta`

Step-by-step explanation

Given;

`\begin{gathered} x=5cos^2\theta \\ y=5cos\theta\:sin\theta \end{gathered}`

Convert from polar form to parametric form.

`\begin{gathered} x(\theta)=r(\theta)cos\theta \\ y(\theta)=r(\theta)sin\theta \end{gathered}`

Here;

`\begin{gathered} x(\theta)=5(cos\theta)^2=5cos\theta* cos\theta \\ y(\theta)=5cos\theta s\imaginaryI n\theta=5cos\theta sin\theta \\ \Rightarrow r(\theta)=5cos\theta \end{gathered}`