Question

the table displays the scores of students on a recent exam find the mean of the scores to the nearest tenth

Answer 1

In this case, the number of students refers to frequencies.

To find the mean, we have to use the following formula

`\begin{gathered} \bar{x}=(\Sigma(x\cdot f))/(N)=(65\cdot4+70\cdot1+75\cdot7+80\cdot5+85\cdot8+90\cdot3+95\cdot4+100\cdot1)/(33) \\ \bar{x}=(260+70+525+400+680+270+380+100)/(33) \\ \bar{x}=(2685)/(33) \\ \bar{x}\approx81.4 \end{gathered}`

Hence, the mean is 81.4.