Question

Consider sample (A) containing 5.99 x 1023 molecules (formula units) of ammonium carbonateand sample (B) containing 93.5 g of ammonium carbonate. Which sample contains more molesof ammonium carbonate? You must support your answer with calculation(s).

Answer 1

Answer: Sample A has 0.995 moles, this is bigger than the moles of Sample B that has 0.973 moles.

Step by step solutions:

1. Convert Molecules of sample A into moles:

1 mole of A contains 6.022x10^23 molecules

∴ x moles A contains 5.99x10^23 molecules

Then, moles of A = (5.99x10^23 /6.022x10^23 )molecules

=5.99/6.02

=0.995moles of A Sample

2. Convert Mass of Sample B into moles :

Given that -

Mass = 93.5g

Mol Mass Ammonium carbonate (NH4)2CO3= 96,09 g/mol

∴ moles B = mass /molecular mass

=93.5g /96.09g/mol

=0.973 moles of sample B

3. Compare the moles of Sample A and B

Conclusion: Sample A has 0.995 moles, this is bigger that the moles of Sample B that has 0.973 moles.