Question

Solve for b. 2 b + 5 = 20 – 6 3 b -

Answer 1

`(2)/(3)b+5=20-b`

start by bringing all b's to one side of the equation and all constants to the other

`(2)/(3)b+b=20-5`

simplify both sides, remembering that 1 can be written as 3/3

`(2)/(3)b+(3)/(3)b=20-5`

since the fractions have the same denominator, we mantain the denominator and add the numerator together

`(5)/(3)b=15`

multiply both sides by 3

`\begin{gathered} (3\cdot5)/(3)b=15\cdot3 \\ 5b=45 \end{gathered}`

divide both sides by 5

`\begin{gathered} (5)/(5)b=(45)/(5) \\ b=9 \end{gathered}`