Question

What is the relationship between the ratios of sin x° and cos y°?

Answer 1

Given the right triangle;

`\begin{gathered} \sin\theta=(opposite)/(hypotenuse),\cos\theta=(adjacent)/(hypotenuse) \\ \end{gathered}`

Thus;

`\sin x=(6)/(10),\cos y=(6)/(10)`

ANSWER: The ratios are both identical