Question

A group of data items and their mean are given. Find a. the deviation from the mean for each of the data items and b. the sum of the deviations in part a

Answer 1

Mean = 62

Subtract each value to the mean

62 - 57 = 5

62 - 57 = 5

62 - 59 = 3

62-62 = 0

62 - 62 = 0

62 -62 = 0

l62-63l = 1

l62-64l = 2

l62-67l= 5

l62-67l= 5

Sum : 5 + 5 + 3 + 1 + 2 + 5 + 5 = 26

Correct option:

5,5,3,0,0,0,1,2,5,5 ; 26