Question

Given the unit circle what is the value of x

Answer 1

Given:

`(x,(3)/(4))\text{ and (1,0) points lies on the circle.}`

Equation of circle is

`x^2+y^2=r^2`
`\begin{gathered} x^2+((3)/(4))^2=1^2 \\ x^2+(9)/(16)=1 \\ x^2=1-(9)/(16) \\ x^2=(16-9)/(16) \\ x^2=(7)/(16) \\ x=-\frac{\sqrt[]{7}}{4} \end{gathered}`