Question

Hi so I’m doing this assignment and got stuck on this question if you can you help me

Answer 1

The Solution:

Given:

`√(\left(x-6\right))* √(\left(x+3\right))`

Required:

To determine the range of values for x.

Applying the rule of radicals that states that:

`\begin{gathered} √(a)*√(b)=√(a* b) \\ Where\text{ }a\ge0,b\ge0 \end{gathered}`

We have:

`\begin{gathered} √(\left(x-6\right))*√(\left(x+3\right))=√((x-6)(x+3)) \\ \\ Where \\ x-6\ge0\text{ } \\ x\ge6\text{ } \end{gathered}`

Therefore, the correct answer is [option A]