Question

Type your numen response in the space provided Given ABC where AC = 7.12 cm BC= 7.12 an, and AB = 7.12 cm then the m/B =

Answer 1

`\begin{gathered} \text{Use cosine rule,} \\ AC^2=AB^2+BC^2-2* AB* BC*\cos B \\ (7.12)^2=(7.12)^2+(7.12)^2-2*7.12*7.12*\cos B \\ \cos B=(1)/(2) \\ B=60^(\circ) \\ \end{gathered}`

You can also find the angle B by just seeing, because every sides are equal.

And it makes equilateral triangle.

And equilateral triangle has every angle as 60 Degree.