Question

Given that BEis a midsegment in triangle ACD solve for the value of x in the triangle below. Show your workM

Answer 1

`\begin{gathered} \text{ By thales' theorem:} \\ (AB)/(20)=(AC)/(x+5),\text{ since BC is a midsegment, AB=BC, thus AB+BC=AC, 2AB=AC} \\ \\ (AB)/(20)=(2AB)/(x+5) \\ \\ (1)/(20)=(2)/(x+5) \\ \\ x+5=20\cdot2 \\ \\ x+5=40 \\ x=40-5 \\ x=35 \end{gathered}`