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(The angle bisectors) Math Help Quick Please!

(The angle bisectors) Math Help Quick Please!-example-1
asked
User Agaase
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2 Answers

12 votes

Answer:

Answer:

m∠WPY = 92°

m∠WQZ = 18°

WZ = 22

answered
User Crenate
by
7.8k points
10 votes

Answer:

m∠WPY = 92°

m∠WQZ = 18°

WZ = 22

Explanation:

PZ is the angle bisector of m∠QPR

and m∠QPR = m∠WPY

So m∠WPZ = half of m∠QPR = half of m∠WPY

If m∠WPZ = 46° ⇒ m∠WPY = 46 x 2 = 92°

If m∠XRY = 52° and m∠WPY = 92° then

m∠WQX = 180 - 52 - 92 = 36°

If QZ is the angle bisector of m∠PQR and m∠PQR = m∠WQX

then m∠WQZ = half of m∠WQX = 1/2 of 36 = 18°

ΔWQZ ≅ ΔQXZ

so WZ = XZ = 22

answered
User Will Warner
by
8.2k points

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