Question

How many grams of BaCl2 are required to prepare 546 g of a 17.9% (m/m) solution?

Answer 1

Mass percent (%m/m) is calculated by working out the mass of solute in grams per of the solution in grams:

`\begin{gathered} mass\text{ }percent=\frac{mass\text{ }of\text{ }solute}{mass\text{ }of\text{ }solution}*100 \\ 17.9\%=\frac{x}{546\text{ }g}*100 \\ \\ 0.179=(x)/(546g) \\ x=0.179*546g \\ x=97.7g \end{gathered}`

Answer: 97.7g of BaCl2 is needed.