What is the y-intercept of the graph of y = 0.5(x - 2)^2 + c, where c is a constant?

Question

asked Jun 9, 2023 122k views

1 Answer

Effel · Answer 1 · 2023-06-13T10:59:26+0000

We are given the equation :

$y=0.5(x-2)^2\text{ + c}$

The y-intercept of the graph is the value of y when x = 0.

When x = 0,

$\begin{gathered} y=0.5(0-2)^2\text{ + c} \\ y\text{ = }0.5(-2)^2\text{ + c} \\ y\text{ = 0.5 }*\text{ 4 + c} \\ y\text{ = 2 + c} \end{gathered}$

Hence the y-intercept of the graph/equation is 2 + c, where c is a constant

Answer: 2 + c