Question

Y=x^2-6x+2 write vertex form

Answer 1

Given:

The equation is y = x²-6x+2.

The objective is to write the equation in vertex form.

The equation can be converted into a perfect square equation by adding +9 on both sides of the equation.

`\begin{gathered} y=x^2-6x+2 \\ y+9=x^2-6x+9+2 \\ y=x^2-6x+9+2-9 \\ y=\lbrack(x-3)(x-3)\rbrack-7 \\ y=(x-3)^2-7 \end{gathered}`