Question

What is the critical angle if a ray of light in Sodium Chloride (n=1.54) is headed into Quartz (n=1.46)?0.649⁰0.948°71.4°40.5°

Answer 1

We can find the critical angle as follows:

`\begin{gathered} \theta_c=sin^(-1)((n2)/(n1)) \\ \theta_c=sin^(-1)((1.46)/(1.54)) \\ \theta_c\approx71.4 \end{gathered}`

Answer:

71.4⁰