Question

finitions of f(x) and g(c) below, find the valuef(x) = x2 – 63 - 66x 6g(x) = -3x + 11gx=Submit Answer

Answer 1

Given:

`\begin{gathered} f(x)=x^2-6x-6 \\ \\ g(x)=-3x+11 \end{gathered}`

Find-: g(f(5))

So:

`\begin{gathered} g(x)=-3x+11 \\ \\ g(f(x))=-3(x^2-6x-6)+11 \\ \\ g(f(x))=-3x^2+18x+18+11 \\ \\ g(f(x))=-3x^2+18x+29 \end{gathered}`

So the value of g(f(5))

`\begin{gathered} g(f(x))=-3x^2+18x+29 \\ \\ g(f(5))=-3(5)^2+18(5)+29 \\ \\ g(f(5))=(-3*25)+(18*5)+29 \\ \\ g(f(5))=-75+90+29 \\ \\ g(f(5))=-75+119 \\ \\ g(f(5))=44 \end{gathered}`

So the value of g(f(5)) is 44