Question

If-8(y-10) = 160, what is the value of 3y

Answer 1

First, we need to find the value of y, using the equation given

`-8\mleft(y-10\mright)=160`

then we need to simplify

`-8y+80=160`

we sum like terms

`-8y=160-80`
`-8y=80`

then we isolate the y

`y=(80)/(-8)`
`y=-10`

then for the value of 3y, we substitute the y=-10

`3\mleft(-10\mright)=-30`