Question

Solve the inequality. Express you answer in interval notation. -3(x + 2) > 15 or x-3< -1

Answer 1

We are told to solve the inequality

`-3\mleft(x+2\mright)>15\text{ or }x-3<-1​`

This becomes

`\begin{gathered} -3(x+2)>15\text{ or }x-3<-1​ \\ -3x-6>15\text{ or }x<2 \\ -3x>11\text{ or }x<2 \\ x<-(11)/(3)\text{ or }x<2 \end{gathered}`

In interval notation, this becomes

`(-\infty,-(11)/(3))\cup(-\infty,2)`