How many solutions will each equation have?x^2+4x+4

Question

asked Feb 17, 2023 228k views

1 Answer

MStodd · Answer 1 · 2023-02-20T23:14:16+0000

To solve this quadratic equation, factor the expression and find the values of x

$\begin{gathered} x^2+4x+4=0 \\ (x+2)(x+2)=0 \\ (x+2)^2=0 \\ x+2=0 \\ x=-2 \end{gathered}$

In this case, there is only one solution for the equation, which is -2.