Question

What is the exact value of sin(csc^-1 (2)), when 0° < A < 180°

Answer 1

We have the expression:

`\sin (\csc ^(-1)(2))`

`0When we operate the function, we will get:[tex]\sin (\csc ^(-1)(2))=(1)/(2)`

That is, since:

`\csc ^(-1)(2)=(\pi)/(6)`

and then:

`\sin ((\pi)/(6))=(1)/(2)`