Question

Question 5 : At how many turning points can the graph of f (x) have ?

Answer 1

Let the given equation be,

`^{}f(x)=x^3-x^2-x+1`

Take the derivative of the function implies,

`f^(\prime)(x)=3x^2-2x-1`

Put f'(x)=0 gives,

`3x^2-2x-1=0`

Since, it is a quadratic equation having two roots. Therefore, the number of turning points will be 2.

Hence, Option B.