Question

What pressure would 0.150 moles of nitrogen gas have (given a temperature of 300 K and a volume of 8.90 L)?

Answer 1

PV = nRT

P = Pressure = ?

V=Volume = 8.90 L

n=number of moles = 0.150 mol

R=constant = 8314 L·Pa/K·mol)

T=Temperature = 300K

P*8.9 = 0.150*8314*300

P*8.9 = 37413

P = 37413/8.9

P=4203.7 Pa