Question

Using the following equation, find the center and radius of the circle. You must show and explain all work and calculations to receive credit. Be sure to leave your answer in exact form.x^2+y^2+8x-6y-15=0

Answer 1

Step-by-step explanation:

The equation of a circle is in the following form:

`\begin{gathered} (x\text{ - h\rparen}^2\text{ +\lparen y-k\rparen}^2\text{ = r}^2 \\ The\text{ center is found at \lparen h,k\rparen and the radius is r} \end{gathered}`

h = -4 and k = 3. r^2 = 40

Answer:

Center of the circle: (-4,3)

Radius:

`\begin{gathered} r\text{ = }\sqrt[]{40} \\ r\text{ = 2}√(10) \end{gathered}`