Question

Determine if the function f(x)=x^2+x is even, odd or neither

Answer 1

Given:

`f(x)=x^2+x`

To determine the function is even, odd, or neither,

`\begin{gathered} f(-x)=f(x)\ldots\text{.. even function} \\ f(-x)=-f(x)\ldots\text{.. Odd function} \end{gathered}`

Replace x with -x,

`f(-x)=(-x)^2+(-x)=x^2-x`

It shows that the given function is neither even nor odd.