Question

I am trying to learn how to do equations like this

Answer 1

The figure is a right triangle since one of its inner angles measures 90°.

Since we are dealing with a right triangle, we can use the following trigonometric identity.

`\tan \theta=(O)/(A)`

Where theta is an inner angle of the triangle different from the 90°-angle one, O is the opposite side to theta, and A is the adjacent side to that angle.

Therefore, in our case,

`\theta=55degree,O=y,A=43`

Thus,

`\begin{gathered} \Rightarrow\tan \theta=\tan (55degree)=(y)/(43) \\ \Rightarrow y=43\cdot\tan (55dgr)=61.41 \\ \Rightarrow y=61.41 \end{gathered}`

Hence, the answer is y=61.41.