Question

Find the area of the smaller sector formed by NMP. Round your answer to the nearest hundredth.

Answer 1

Given:

`\begin{gathered} \theta=60^0 \\ r=12cm \end{gathered}`

The area of sector is given by;

`\begin{gathered} A=(\theta)/(360)*\pi r^2 \\ A=(60)/(360)*\pi*12^2 \\ A=(8640\pi)/(360) \\ A=24\pi \\ A=75.398 \\ \\ To\text{ the nearest hundredth,} \\ A=75.40cm^2 \end{gathered}`

Therefore, the area of the smaller sector to the nearest hundredth is 75.40 centimeters square.