Question

What is the limiting reagent when 1.5 moles of nitrogen react with 6 moles of hydrogen? N2(g)+3H2(g)—> 2NH3(g)

Answer 1

Step-by-step explanation

Given

N2(g)+3H2(g)—> 2NH3(g)

Number of moles of nitrogen = 1.5 moles

Number of moles of hydrogen = 6 moles

Required: Limiting reagent

Solution

For Nitrogen:

`\begin{gathered} 1,5\text{ mol N x }\frac{2\text{ mol NH}_3}{1\text{ mol N}_2} \\ \\ Moles\text{ of NH}_3=3\text{ mol} \end{gathered}`

For Hydrogen:

`\begin{gathered} 6\text{ mol H x }\frac{2\text{ mol NH}_3}{3\text{ mol H}_2} \\ \\ Moles\text{ of NH}_3=\text{ 4 mol} \end{gathered}`

The limiting reagent is Nitrogen, because less moles of NH3 will be produced by nitrogen, meaning it all of it gets used up.

Answer

The limiting reagent is Nitrogen.