Question

What are the domain and range of the real-valued function f(x) = – 3+ V4x12?Need help with this practice question

Answer 1

The domain and range of the function are:

The domain is x ≥ 3.

The Range is: f(x) ≥ -3

How to find the domain and the range?

The domain of a function is the set of all possible input values for which the function can be defined, while the range is the set of all possible output values generated by the function.

The function is given as:

f(x) = -3 + √(4x - 12)

Now, we can see that any value of x less than 3 will create a negative root which is not a real number.

Thus, the domain is x ≥ 3.

At the minimum value of x, f(x) = -3. Thus:

Range is: f(x) ≥ -3

Answer 2

The domain of a function f(x) is the set of all input values for which the function is real and defined.

The range of the function is the set of all values that f(x) takes. This means the set of values the dependent variable takes for which the function is defined.

Given:

`f(x)=-3+\sqrt[]{4x-12}`