Question

Light enter the container of the liquid at the angle 37° to the normal refraction beam makes an angle of 27° with the normal. Calculate the index of the liquid

Answer 1

Answer: 1.33

Step-by-step explanation:

We would apply Snell's law which is expressed as

niSinθi = nrSinθr

where

θi = angle of incidence

θr = angle of refraction

ni = index of refraction of the incident medium(air)

nr = index of refraction of the refractive medium(liquid in this case)

From the information given,

ni = 1(index for air)

θi = 37

θr = 27

By substituting these values into the formula, we have

1 * sin37 = nr * sin27

nr = sin37/sin27

nr = 1.33

The index of the liquid is 1.33