Question

Solve the equation on theinterval [0, 2π).cos x 1 = -cos xπ[]Xx = 10 T??

Answer 1

`x=(\pi)/(3), (5\pi)/(3)`

Explanation:

W have the following equation:

`\cos x-1=-\cos x`

We solve for x:

`\begin{gathered} \cos x-1=-\cos x \\ \\ \cos x=u \\ \\ u-1=-u \\ \\ u+u-1=0 \\ \\ 2u=1 \\ \\ u=(1)/(2) \\ \\ \cos x=(1)/(2) \\ \\ x=(\pi)/(3),(5\pi)/(3) \end{gathered}`