Question

Hello can I please have some assistance with this problem

Answer 1

The equation is given

`25x^2+81y^2=1`

To determine y-intercept substitute x=0

`0+81y^2=1`
`y^2=(1)/(81)`
`y=\sqrt[]{(1)/(81)}=\pm(1)/(9)`

To determine the x-intercept , substitute y=0

`25x^2+0=1`
`x^{}=\sqrt[]{(1)/(25)}=\pm(1)/(5)`

Hence the x-intercepts are

`(1)/(5),-(1)/(5)`

The y-intercepts are

`(1)/(9),(-1)/(9)`